(7x-4)(4x^2-19x-5)=0

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Solution for (7x-4)(4x^2-19x-5)=0 equation: 


Simplifying
(7x + -4)(4x2 + -19x + -5) = 0

Reorder the terms:
(-4 + 7x)(4x2 + -19x + -5) = 0

Reorder the terms:
(-4 + 7x)(-5 + -19x + 4x2) = 0

Multiply (-4 + 7x) * (-5 + -19x + 4x2)
(-4(-5 + -19x + 4x2) + 7x * (-5 + -19x + 4x2)) = 0
((-5 * -4 + -19x * -4 + 4x2 * -4) + 7x * (-5 + -19x + 4x2)) = 0
((20 + 76x + -16x2) + 7x * (-5 + -19x + 4x2)) = 0
(20 + 76x + -16x2 + (-5 * 7x + -19x * 7x + 4x2 * 7x)) = 0
(20 + 76x + -16x2 + (-35x + -133x2 + 28x3)) = 0

Reorder the terms:
(20 + 76x + -35x + -16x2 + -133x2 + 28x3) = 0

Combine like terms: 76x + -35x = 41x
(20 + 41x + -16x2 + -133x2 + 28x3) = 0

Combine like terms: -16x2 + -133x2 = -149x2
(20 + 41x + -149x2 + 28x3) = 0

Solving
20 + 41x + -149x2 + 28x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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